What is the critical (x+1)/(x^2-5x+4) ?

The critical (x+1)/(x^2-5x+4) is x=-1-sqrt(10),x=sqrt(10)-1

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critical (x+1)/(x^2-5x+4)

critical points

\frac{x + 1}{x ^{2} - 5 x + 4}

x = - 1 - 10, x = 10 - 1

Solution steps

\frac{x + 1}{x ^{2} - 5 x + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1 - 10, x = 10 - 1, x = 1, x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x + 1}{x ^{2} - 5 x + 4} : x < 1 or 1 < x < 4 or x > 4

\frac{x + 1}{x ^{2} - 5 x + 4}

is not defined at

x = 1, x = 4

, therefore:

x = - 1 - 10, x = 10 - 1

f (x) = x^{3} + 6 x^{2}

f (x) = 2 x^{3} - 6 x^{2} - 48 x + 10

2 x^{3} + 3 x^{2} - 12 x + 4

2 x^{3} + 3 x^{2} - 12 x + 7

\frac{( x ^{2} )}{x ^{2} + 3}

What is the critical (x+1)/(x^2-5x+4) ?
The critical (x+1)/(x^2-5x+4) is x=-1-sqrt(10),x=sqrt(10)-1