What is the critical ((x^2-1))/(x^2-4) ?

The critical ((x^2-1))/(x^2-4) is x=0

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critical ((x^2-1))/(x^2-4)

critical points

\frac{( x ^{2} - 1 )}{x ^{2} - 4}

x = 0

Solution steps

\frac{x ^{2} - 1}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 1}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{x ^{2} - 1}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

f (x) = x^{3} + 4.5 x^{2} - 12 x - 2

\frac{1}{x ^{2} + 9}

f (x) = (x - a) (x + a)^{3}

f (x) = 3 x^{3} - 9 x y + 3 y^{3}

f (x, y) = x^{2} + 2 a x y + y^{2}