What is the perpendicular y=-8x+7,(5,-3) ?

The perpendicular y=-8x+7,(5,-3) is y= 1/8 x-29/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=-8x+7,(5,-3)

perpendicular

y = - 8 x + 7, (5, - 3)

y = \frac{1}{8} x - \frac{29}{8}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 8 x + 7

that passes through

(5, - 3)

Find the slope of

y = - 8 x + 7 : m = - 8

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(5, - 3) : y = \frac{1}{8} x - \frac{29}{8}

y = \frac{1}{8} x - \frac{29}{8}

f (x) = x^{4} - 12 x^{3} + 16 x^{2}

f (x) = \frac{x + 7}{x ^{3} - 3 x ^{2} + 5 x + 2}

\frac{x + 2}{x - 5}

5 x^{4} - 30 x^{2}

f (x) = \frac{( t + 1 )}{t}

What is the perpendicular y=-8x+7,(5,-3) ?
The perpendicular y=-8x+7,(5,-3) is y= 1/8 x-29/8