What is the critical f(x)=-2x^2ln(x)+21x^2 ?

The critical f(x)=-2x^2ln(x)+21x^2 is x=e^{10}

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critical f(x)=-2x^2ln(x)+21x^2

critical points

f (x) = - 2 x^{2} ln (x) + 21 x^{2}

x = e^{10}

Solution steps

- 2 x^{2} ln (x) + 21 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = e^{10}, x = 0

Identify critical points not in

f (x)

domain

Domain of

- 2 x^{2} ln (x) + 21 x^{2} : x > 0

- 2 x^{2} ln (x) + 21 x^{2}

is not defined at

x = 0

, therefore:

x = e^{10}

f (x) = 3 x^{2} y + y^{3} - 3 x^{2} + 2

f (x) = \frac{1}{4} x^{4} - \frac{1}{3} x^{3} - 3 x^{2}

f (x) = \frac{5 x ^{2}}{( x ^{2} - 16 )}

f (x) = x^{3} + 2 x y - 6 x - 4 y^{2}

f (x) = x^{3} - 26 x^{2}

What is the critical f(x)=-2x^2ln(x)+21x^2 ?
The critical f(x)=-2x^2ln(x)+21x^2 is x=e^{10}