What is the critical f(x)=-(2x)/((x^2-1)^2) ?

The critical f(x)=-(2x)/((x^2-1)^2) is None

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critical f(x)=-(2x)/((x^2-1)^2)

critical points

f (x) = - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

None

Solution steps

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

- \frac{2 x}{( x ^{2} - 1 ) ^{2}} : x < - 1 or - 1 < x < 1 or x > 1

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

is not defined at

x = - 1, x = 1

, therefore:

None

f (x, y) = 10 + 2 x^{4} - 8 x^{2} + 4 x y - y^{2}

f (x) = x^{\frac{1}{3}} (2 x^{2} - 8)

f (x) = - x^{2} + 14 x

f (x) = cos (\frac{π x}{2})

3 x^{5} + 5 x^{3}

What is the critical f(x)=-(2x)/((x^2-1)^2) ?
The critical f(x)=-(2x)/((x^2-1)^2) is None