What is the critical (3x^2)/((x^2-4)) ?

The critical (3x^2)/((x^2-4)) is x=0

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critical (3x^2)/((x^2-4))

critical points

\frac{3 x ^{2}}{( x ^{2} - 4 )}

x = 0

Solution steps

\frac{3 x ^{2}}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x ^{2}}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{3 x ^{2}}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

f (x) = - \frac{1}{5}

+ x^{2} + 6 x + 5

\frac{x ^{2} - 7}{x - 4}

f (x) = 3 x^{2} + 18 x + 24

6 x 100 - x^{2}