What is the critical f(x)= x/(x^2+8x+12) ?

The critical f(x)= x/(x^2+8x+12) is x=-2sqrt(3),x=2sqrt(3)

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critical f(x)= x/(x^2+8x+12)

critical points

f (x) = \frac{x}{x ^{2} + 8 x + 12}

x = - 23, x = 23

Solution steps

\frac{x}{x ^{2} + 8 x + 12}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 23, x = 23, x = - 6, x = - 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 8 x + 12} : x < - 6 or - 6 < x < - 2 or x > - 2

\frac{x}{x ^{2} + 8 x + 12}

is not defined at

x = - 6, x = - 2

, therefore:

x = - 23, x = 23

x^{3} - 3 x (y - 2) + (y - 2)^{3}

(x^{2} - 8 x) (y^{2} - 2 y)

f (x) = \frac{x ^{2} ( x - 4 )}{x + 6}

f (x) = 12 x^{5} + 45 x^{4} - 360 x^{3} + 7

x^{3} - 6 x^{2} + 9 x + 5

What is the critical f(x)= x/(x^2+8x+12) ?
The critical f(x)= x/(x^2+8x+12) is x=-2sqrt(3),x=2sqrt(3)