What is the critical x/(x^2+11x+28) ?

The critical x/(x^2+11x+28) is x=-2sqrt(7),x=2sqrt(7)

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critical x/(x^2+11x+28)

critical points

\frac{x}{x ^{2} + 11 x + 28}

x = - 27, x = 27

Solution steps

\frac{x}{x ^{2} + 11 x + 28}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 27, x = 27, x = - 7, x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 11 x + 28} : x < - 7 or - 7 < x < - 4 or x > - 4

\frac{x}{x ^{2} + 11 x + 28}

is not defined at

x = - 7, x = - 4

, therefore:

x = - 27, x = 27

f (x) = \frac{3}{x ^{2} + 1}

f (x) = x^{2} + \frac{128}{x}

f (x) = 5 a x - 2 x^{2}

\frac{6 x ^{2} + 2 x - 3}{x - 4}

f (x) = 2 x^{3} + 3 x^{2} - 72 x + 7

What is the critical x/(x^2+11x+28) ?
The critical x/(x^2+11x+28) is x=-2sqrt(7),x=2sqrt(7)