What is the critical y=x^2+1/(x^2) ?

The critical y=x^2+1/(x^2) is x=-1,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical y=x^2+1/(x^2)

critical points

y = x^{2} + \frac{1}{x ^{2}}

x = - 1, x = 1

Solution steps

x^{2} + \frac{1}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} + \frac{1}{x ^{2}} : x < 0 or x > 0

x^{2} + \frac{1}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

F (x) = x^{\frac{4}{5}} (x - 9)^{2}

x^{3} - 6 x + 5

x^{3} - 6 x + 2

f (x) = 2 x 4 - x^{2}

f (x) = e^{x^{2} - 9 x - 1}