What is the critical f(x)=x^3-x^2+3 ?

The critical f(x)=x^3-x^2+3 is x=0,x= 2/3

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critical f(x)=x^3-x^2+3

critical points

f (x) = x^{3} - x^{2} + 3

x = 0, x = \frac{2}{3}

Solution steps

x^{3} - x^{2} + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} - x^{2} + 3 : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{2}{3}

f (x) = (x + 2) \frac{1}{5}

(3.3) (3.4)

f (x) = - 3 x + y = 3

f (x) = \frac{3 x - 6}{x}

\frac{2}{x + 8}