What is the critical f(x)=2x^3+12xy-6y^2 ?

The critical f(x)=2x^3+12xy-6y^2 is (0,0),(-2,-2)

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critical f(x)=2x^3+12xy-6y^2

critical points

f (x) = 2 x^{3} + 12 x y - 6 y^{2}

(0, 0), (- 2, - 2)

Solution steps

2 x^{3} + 12 x y - 6 y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (- 2, - 2)

f (x) = ln (8 + 27 x^{3})

f (x) = sin^{2} (5 x) + cos (5 x), 0 < x < \frac{2 π}{5}

f (x) = 3 x + 5 x^{- 1}

(x^{2} - 1)^{\frac{2}{3}}

4 x^{2}

What is the critical f(x)=2x^3+12xy-6y^2 ?
The critical f(x)=2x^3+12xy-6y^2 is (0,0),(-2,-2)