What is the critical f(x)=((x^4+1))/(x^2) ?

The critical f(x)=((x^4+1))/(x^2) is x=-1,x=1

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critical f(x)=((x^4+1))/(x^2)

critical points

f (x) = \frac{( x ^{4} + 1 )}{x ^{2}}

x = - 1, x = 1

Solution steps

\frac{x ^{4} + 1}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{4} + 1}{x ^{2}} : x < 0 or x > 0

\frac{x ^{4} + 1}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

f (x) = 2 x^{5} - 2 x^{4} + 3 x^{3} - x + 1

x - 6 x - 1

x - 3 ln (x)

y^{1} = x^{2} - 3 x + 2

f (x) = x^{3} + 12 x^{2} - 27 x + 3

What is the critical f(x)=((x^4+1))/(x^2) ?
The critical f(x)=((x^4+1))/(x^2) is x=-1,x=1