What is the critical f(x)=-2x^2ln(x)+9x^2 ?

The critical f(x)=-2x^2ln(x)+9x^2 is x=e^4

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critical f(x)=-2x^2ln(x)+9x^2

critical points

f (x) = - 2 x^{2} ln (x) + 9 x^{2}

x = e^{4}

Solution steps

- 2 x^{2} ln (x) + 9 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = e^{4}, x = 0

Identify critical points not in

f (x)

domain

Domain of

- 2 x^{2} ln (x) + 9 x^{2} : x > 0

- 2 x^{2} ln (x) + 9 x^{2}

is not defined at

x = 0

, therefore:

x = e^{4}

f (x) = - 4 x e^{6 x}

f (x) = - x^{3} + 6 x^{2} + x + 1

f (x, y) = (x^{2} - 8 x) (y^{2} - 5 y)

f (x) = x^{3} + 6 x^{2} - 135 x + 10

- cos (x - \frac{π}{2})

What is the critical f(x)=-2x^2ln(x)+9x^2 ?
The critical f(x)=-2x^2ln(x)+9x^2 is x=e^4