What is the critical-(2x)/((x^2-1)^2) ?

The critical-(2x)/((x^2-1)^2) is None

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critical-(2x)/((x^2-1)^2)

critical points

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

None

Solution steps

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

- \frac{2 x}{( x ^{2} - 1 ) ^{2}} : x < - 1 or - 1 < x < 1 or x > 1

- \frac{2 x}{( x ^{2} - 1 ) ^{2}}

is not defined at

x = - 1, x = 1

, therefore:

None

\frac{t ^{2} - 1}{e ^{t^{2}}}

f (x) = \frac{( - 5 x ^{2} - x )}{e ^{x}}

y = \frac{x ^{2} - 6 x + 12}{x - 4}

f (x) = x^{2} + \frac{9}{x ^{2}}

f (x) = x^{2} + y^{2} - x y + 10 x - 2 y