What is the asymptotes of f(x)= 1/(x^2-4) ?

The asymptotes of f(x)= 1/(x^2-4) is Vertical: x=-2,x=2,Horizontal: y=0

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asymptotes of f(x)= 1/(x^2-4)

asymptotes

f (x) = \frac{1}{x ^{2} - 4}

Vertical : x = - 2, x = 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 4} : x = - 2, x = 2

Horizontal Asymptotes of

\frac{1}{x ^{2} - 4} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 4} :

None

Vertical : x = - 2, x = 2, Horizontal : y = 0

f (x) = \frac{3 x ^{2} - 2 x}{x + 2 x ^{2}}

f (x) = \frac{5 x - 1}{4 x + 2}

f (x) = \frac{x ^{3}}{x ^{2} + 1}

f (x) = \frac{x ^{5} + 1}{( x ^{2} - 2 ) ^{2}}

f (x) = \frac{5 x ^{2} + 3 x - 2}{x ^{3} - 8}

What is the asymptotes of f(x)= 1/(x^2-4) ?
The asymptotes of f(x)= 1/(x^2-4) is Vertical: x=-2,x=2,Horizontal: y=0