What is the asymptotes of f(x)= x/(sqrt(x^2-9)) ?

The asymptotes of f(x)= x/(sqrt(x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=1,y=-1

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asymptotes of f(x)= x/(sqrt(x^2-9))

asymptotes

f (x) = \frac{x}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 1, y = - 1

Solution steps

Vertical asymptotes of

\frac{x}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x}{x ^{2} - 9} : y = 1, y = - 1

Slant Asymptotes of

\frac{x}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 1, y = - 1

\frac{2 x ^{2} - 3 x - 1}{2 x + 1}

x ln (1 - \frac{2}{x})

f (x) = \frac{2 x - 2}{x ^{2} + x} + 1

f (x) = \frac{x - 3}{x ^{2} + 3}

f (x) = \frac{x ^{2} + x + 1}{x}

What is the asymptotes of f(x)= x/(sqrt(x^2-9)) ?
The asymptotes of f(x)= x/(sqrt(x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=1,y=-1