What is the asymptotes of f(x)=(3x+6)/(x^2+8x-9) ?

The asymptotes of f(x)=(3x+6)/(x^2+8x-9) is Vertical: x=-9,x=1,Horizontal: y=0

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asymptotes of f(x)=(3x+6)/(x^2+8x-9)

asymptotes

f (x) = \frac{3 x + 6}{x ^{2} + 8 x - 9}

Vertical : x = - 9, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{3 x + 6}{x ^{2} + 8 x - 9} : x = - 9, x = 1

Horizontal Asymptotes of

\frac{3 x + 6}{x ^{2} + 8 x - 9} : y = 0

Slant Asymptotes of

\frac{3 x + 6}{x ^{2} + 8 x - 9} :

None

Vertical : x = - 9, x = 1, Horizontal : y = 0

f (x) = \frac{3 + x - x ^{2}}{x - 2}

f (x) = \frac{2 x - 8}{- 3 x - 4}

f (x) = \frac{3 x - 18}{2 x + 1}

y = tan (x)

f (x) = \frac{5 x}{2 x - 5}

What is the asymptotes of f(x)=(3x+6)/(x^2+8x-9) ?
The asymptotes of f(x)=(3x+6)/(x^2+8x-9) is Vertical: x=-9,x=1,Horizontal: y=0