What is the asymptotes of f(x)=log_{6}(x+1)+5 ?

The asymptotes of f(x)=log_{6}(x+1)+5 is Vertical: x=-1

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asymptotes of f(x)=log_{6}(x+1)+5

asymptotes

f (x) = lo g_{6} (x + 1) + 5

Vertical : x = - 1

Solution steps

Vertical asymptotes of

lo g_{6} (x + 1) + 5 : x = - 1

Horizontal Asymptotes of

lo g_{6} (x + 1) + 5 :

None

Slant Asymptotes of

lo g_{6} (x + 1) + 5 :

None

Vertical : x = - 1

\frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

\frac{x ^{3}}{x + 1}

f (x) = \frac{2 e ^{x} + x ^{2}}{x - 1}

f (x) = \frac{x + 3}{2 x ^{2} - 98}

f (x) = \frac{x ^{2} - 2 x - 15}{3 x + 9}

What is the asymptotes of f(x)=log_{6}(x+1)+5 ?
The asymptotes of f(x)=log_{6}(x+1)+5 is Vertical: x=-1