What is the asymptotes of f(x)=(2x^2-10x+1)/(x-5) ?

The asymptotes of f(x)=(2x^2-10x+1)/(x-5) is Vertical: x=5,Slant: y=2x

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asymptotes of f(x)=(2x^2-10x+1)/(x-5)

asymptotes

f (x) = \frac{2 x ^{2} - 10 x + 1}{x - 5}

Vertical : x = 5, Slant : y = 2 x

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 10 x + 1}{x - 5} : x = 5

Horizontal Asymptotes of

\frac{2 x ^{2} - 10 x + 1}{x - 5} :

None

Slant Asymptotes of

\frac{2 x ^{2} - 10 x + 1}{x - 5} : y = 2 x

Vertical : x = 5, Slant : y = 2 x

f (x) = \frac{9 - 4 x ^{2} - 2 x ^{3}}{x ^{2} - 3}

f (x) = \frac{ln ( x + 1 )}{x}

f (x) = \frac{4 x}{2 x + 1}

f (x) = \frac{e ^{x}}{x ^{2}}

f (x) = \frac{2 x + 8}{x ^{2} + x - 12}

What is the asymptotes of f(x)=(2x^2-10x+1)/(x-5) ?
The asymptotes of f(x)=(2x^2-10x+1)/(x-5) is Vertical: x=5,Slant: y=2x