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Popular >

extreme y=x^2e^{-3x}

Solution

extreme points

y = x^{2} e^{- 3 x}

Solution

Minimum (0, 0), Maximum (\frac{2}{3}, \frac{4}{9 e ^{2}})

Solution steps

f^{'} (x) = e^{- 3 x} x (2 - 3 x)

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{2}{3},

Decreasing

: \frac{2}{3} < x < \infty

Plug

x = 0

into

x^{2} e^{- 3 x} : 0

Minimum (0, 0)

Plug

x = \frac{2}{3}

into

x^{2} e^{- 3 x} : \frac{4}{9 e ^{2}}

Maximum (\frac{2}{3}, \frac{4}{9 e ^{2}})

Minimum (0, 0), Maximum (\frac{2}{3}, \frac{4}{9 e ^{2}})

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\frac{x - 5}{2 x + 4}

domain of f(x)= 3/(25-x^2)domain

f (x) = \frac{3}{25 - x ^{2}}

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f (x) = x^{2} 4

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f (x) = \frac{x ^{2} + 5 x + 4}{- 2 x ^{2} - 6 x}

inverse of f(x)= 3/5 x-3 inverse

f (x) = \frac{3}{5} x - 3

Frequently Asked Questions (FAQ)

What is the extreme y=x^2e^{-3x} ?
The extreme y=x^2e^{-3x} is Minimum(0,0),Maximum(2/3 , 4/(9e^2))