What is the asymptotes of f(x)=(x^2)/(-3x^2+1) ?

The asymptotes of f(x)=(x^2)/(-3x^2+1) is Vertical: x=-1/(sqrt(3)),x= 1/(sqrt(3)),Horizontal: y=-1/3

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asymptotes of f(x)=(x^2)/(-3x^2+1)

asymptotes

f (x) = \frac{x ^{2}}{- 3 x ^{2} + 1}

Vertical : x = - \frac{1}{3}, x = \frac{1}{3}, Horizontal : y = - \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2}}{- 3 x ^{2} + 1} : x = - \frac{1}{3}, x = \frac{1}{3}

Horizontal Asymptotes of

\frac{x ^{2}}{- 3 x ^{2} + 1} : y = - \frac{1}{3}

Slant Asymptotes of

\frac{x ^{2}}{- 3 x ^{2} + 1} :

None

Vertical : x = - \frac{1}{3}, x = \frac{1}{3}, Horizontal : y = - \frac{1}{3}

f (x) = \frac{5 x ^{2} - 41 x + 8}{3 x ^{2} - 21 x}

f (x) = \frac{25}{x + 2.3}

f (x) = \frac{x ^{2} + 2 x}{2 x ^{2} - 7 x}

f (x) = x^{2} e^{x}

f (x) = \frac{1}{x - 1} - 2 x

What is the asymptotes of f(x)=(x^2)/(-3x^2+1) ?
The asymptotes of f(x)=(x^2)/(-3x^2+1) is Vertical: x=-1/(sqrt(3)),x= 1/(sqrt(3)),Horizontal: y=-1/3