What is the asymptotes of f(x)=(x^2-5x)/(2x^2) ?

The asymptotes of f(x)=(x^2-5x)/(2x^2) is Vertical: x=0,Horizontal: y= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2-5x)/(2x^2)

asymptotes

f (x) = \frac{x ^{2} - 5 x}{2 x ^{2}}

Vertical : x = 0, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 5 x}{2 x ^{2}} : x = 0

Horizontal Asymptotes of

\frac{x ^{2} - 5 x}{2 x ^{2}} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 5 x}{2 x ^{2}} :

None

Vertical : x = 0, Horizontal : y = \frac{1}{2}

f (x) = \frac{x + 2}{x ^{2} - 16}

f (x) = \frac{x + 2}{x - 3}

f (x) = \frac{x - 6}{x ^{2} + 2 x - 24}

f (x) = \frac{- 4 x + 8}{2 x ^{2} - 8}

f (x) = \frac{1}{( x - 2 ) ^{3}}

What is the asymptotes of f(x)=(x^2-5x)/(2x^2) ?
The asymptotes of f(x)=(x^2-5x)/(2x^2) is Vertical: x=0,Horizontal: y= 1/2