What is the asymptotes of f(x)=(x-7)/(2x^2-16x-40) ?

The asymptotes of f(x)=(x-7)/(2x^2-16x-40) is Vertical: x=-2,x=10,Horizontal: y=0

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asymptotes of f(x)=(x-7)/(2x^2-16x-40)

asymptotes

f (x) = \frac{x - 7}{2 x ^{2} - 16 x - 40}

Vertical : x = - 2, x = 10, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 7}{2 x ^{2} - 16 x - 40} : x = - 2, x = 10

Horizontal Asymptotes of

\frac{x - 7}{2 x ^{2} - 16 x - 40} : y = 0

Slant Asymptotes of

\frac{x - 7}{2 x ^{2} - 16 x - 40} :

None

Vertical : x = - 2, x = 10, Horizontal : y = 0

f (x) = \frac{6}{x}

f (x) = \frac{x ^{2} - 16}{3 x - 12}

f (x) = \frac{15 x - 3}{x ^{2} + 2 x - 35}

f (x) = \frac{x + 2}{x ^{2} - 9}

f (x) = \frac{( 2 - x ) ( 3 x + 1 )}{x ^{2} - 4}

What is the asymptotes of f(x)=(x-7)/(2x^2-16x-40) ?
The asymptotes of f(x)=(x-7)/(2x^2-16x-40) is Vertical: x=-2,x=10,Horizontal: y=0