What is the asymptotes of f(x)=(x^2+4x)/(2x^2-5x) ?

The asymptotes of f(x)=(x^2+4x)/(2x^2-5x) is Vertical: x= 5/2 ,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2+4x)/(2x^2-5x)

asymptotes

f (x) = \frac{x ^{2} + 4 x}{2 x ^{2} - 5 x}

Vertical : x = \frac{5}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 5 x} : x = \frac{5}{2}

Horizontal Asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 5 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 5 x} :

None

Vertical : x = \frac{5}{2}, Horizontal : y = \frac{1}{2}

f (x) = \frac{x ^{2} - 1}{3 x ^{2} - 75}

f (x) = \frac{- 4 x - 4}{3 x - 2}

f (x) = \frac{2 x - 9}{3 x ^{2} - 75}

\frac{x ^{2} + 1}{x ^{3} + 2}

f (x) = \frac{3 x ^{2}}{x - 2}

What is the asymptotes of f(x)=(x^2+4x)/(2x^2-5x) ?
The asymptotes of f(x)=(x^2+4x)/(2x^2-5x) is Vertical: x= 5/2 ,Horizontal: y= 1/2