What is the asymptotes of f(x)=(2x^2-8x-42)/(x+5) ?

The asymptotes of f(x)=(2x^2-8x-42)/(x+5) is Vertical: x=-5,Slant: y=2x-18

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asymptotes of f(x)=(2x^2-8x-42)/(x+5)

asymptotes

f (x) = \frac{2 x ^{2} - 8 x - 42}{x + 5}

Vertical : x = - 5, Slant : y = 2 x - 18

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 8 x - 42}{x + 5} : x = - 5

Horizontal Asymptotes of

\frac{2 x ^{2} - 8 x - 42}{x + 5} :

None

Slant Asymptotes of

\frac{2 x ^{2} - 8 x - 42}{x + 5} : y = 2 x - 18

Vertical : x = - 5, Slant : y = 2 x - 18

f (x) = \frac{2 ( x - 1 )}{x - 8}

f (x) = \frac{x ^{2} - 5 x}{- 3 x ^{2} - 15 x}

f (x) = \frac{2 x ^{2} - 50}{3 x - 1}

f (x) = \frac{- 3 x + 3}{x ^{2} - 6 x + 5}

f (x) = lo g_{10} (x + 5)

What is the asymptotes of f(x)=(2x^2-8x-42)/(x+5) ?
The asymptotes of f(x)=(2x^2-8x-42)/(x+5) is Vertical: x=-5,Slant: y=2x-18