What is the critical 3/4 (x^2-1)^{2/3} ?

The critical 3/4 (x^2-1)^{2/3} is x=-1,x=0,x=1

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critical 3/4 (x^2-1)^{2/3}

critical points

\frac{3}{4} (x^{2} - 1)^{\frac{2}{3}}

x = - 1, x = 0, x = 1

Solution steps

\frac{3}{4} (x^{2} - 1)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{3}{4} (x^{2} - 1)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

4 x^{2} - 5 x + 7

(- 1.3) (3.1)

f (x) = \frac{x ^{2} - 1}{x ^{2} + 1}

8 x - y = 9

x^{4} - 8 x^{3}

What is the critical 3/4 (x^2-1)^{2/3} ?
The critical 3/4 (x^2-1)^{2/3} is x=-1,x=0,x=1