What is the asymptotes of f(x)=(sqrt(x^2-8))/(x-4) ?

The asymptotes of f(x)=(sqrt(x^2-8))/(x-4) is Vertical: x=4,Horizontal: y=1,y=-1

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asymptotes of f(x)=(sqrt(x^2-8))/(x-4)

asymptotes

f (x) = \frac{x ^{2} - 8}{x - 4}

Vertical : x = 4, Horizontal : y = 1, y = - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 8}{x - 4} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 8}{x - 4} : y = 1, y = - 1

Slant Asymptotes of

\frac{x ^{2} - 8}{x - 4} :

None

Vertical : x = 4, Horizontal : y = 1, y = - 1

\frac{2 x - 1}{x e ^{x}}

\frac{1}{2} x - \frac{6}{x}

f (x) = \frac{x - 4}{2 ( x - 1 ) ( x - 4 )}

f (x) = \frac{- 2 x - 6}{x + 3}

f (x) = (\frac{1}{3})^{x} - 1

What is the asymptotes of f(x)=(sqrt(x^2-8))/(x-4) ?
The asymptotes of f(x)=(sqrt(x^2-8))/(x-4) is Vertical: x=4,Horizontal: y=1,y=-1