What is the asymptotes of f(x)=ln(x+1) ?

The asymptotes of f(x)=ln(x+1) is Vertical: x=-1

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asymptotes of f(x)=ln(x+1)

asymptotes

f (x) = ln (x + 1)

Vertical : x = - 1

Solution steps

Vertical asymptotes of

ln (x + 1) : x = - 1

Horizontal Asymptotes of

ln (x + 1) :

None

Slant Asymptotes of

ln (x + 1) :

None

Vertical : x = - 1

f (x) = \frac{x + 6}{x ^{2} - 36}

f (x) = \frac{- 2 x + 8}{x ^{2} - 4 x}

f (x) = 3^{x} - 3

\frac{x}{x ^{2} - 9}

f (x) = \frac{5 x + 3}{2 x ^{2} + 10 x + 8}

What is the asymptotes of f(x)=ln(x+1) ?
The asymptotes of f(x)=ln(x+1) is Vertical: x=-1