What is the asymptotes of f(x)=(x^2+4x)/(2x^2-7x) ?

The asymptotes of f(x)=(x^2+4x)/(2x^2-7x) is Vertical: x= 7/2 ,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2+4x)/(2x^2-7x)

asymptotes

f (x) = \frac{x ^{2} + 4 x}{2 x ^{2} - 7 x}

Vertical : x = \frac{7}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x} : x = \frac{7}{2}

Horizontal Asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 4 x}{2 x ^{2} - 7 x} :

None

Vertical : x = \frac{7}{2}, Horizontal : y = \frac{1}{2}

x^{5} - 5 x

f (x) = \frac{2 x ^{2} + 1}{2 x ^{2} - 3 x}

f (x) = \frac{x ^{2}}{( x - 2 ) ^{2}}

f (x) = 2^{x - 3} + 5

f (x) = \frac{x ^{2} + 3}{x - 2}

What is the asymptotes of f(x)=(x^2+4x)/(2x^2-7x) ?
The asymptotes of f(x)=(x^2+4x)/(2x^2-7x) is Vertical: x= 7/2 ,Horizontal: y= 1/2