变换 1/2 sin(x-pi/2)

解答

变换

\frac{1}{2} sin (x - \frac{π}{2})

相位 : \frac{π}{2}, 垂直 : 0

求解步骤

f (x) = \frac{1}{2} sin (x - \frac{π}{2})

g (B x - C) = sin (x - \frac{π}{2}), B = 1, C = \frac{π}{2}, D = 0

因此，相位变换

\frac{C}{B}

为

\frac{\frac{π}{2}}{1}

\frac{π}{2}

垂直变换

D

为

0

0

f (x) = x^{3} + x^{2} - 16 x - 16

f (x) = 2 x^{2} - 4

\frac{x}{2} + \frac{y}{5} - 1 = 0

f (x) = \frac{4 x + 1}{7}

f (x) = \frac{1}{x - 2}