What is the asymptotes of f(x)= 2/(x^2-1) ?

The asymptotes of f(x)= 2/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=0

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asymptotes of f(x)= 2/(x^2-1)

asymptotes

f (x) = \frac{2}{x ^{2} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{2}{x ^{2} - 1} : y = 0

Slant Asymptotes of

\frac{2}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 0

f (x) = \frac{x ^{2} - 25}{2 x + 10}

y = \frac{x ^{2} - 3 x + 2}{x ^{2} - 4 x + 3}

f (x) = \frac{x ^{2} - 2 x - 3}{- 4 x + 12}

f (x) = \frac{( x - 1 )}{( x ^{2} - 4 )}

f (x) = \frac{5 x + 3}{3 x + 12}

What is the asymptotes of f(x)= 2/(x^2-1) ?
The asymptotes of f(x)= 2/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=0