What is the asymptotes of f(x)=(x^2+3x)/(x+1) ?

The asymptotes of f(x)=(x^2+3x)/(x+1) is Vertical: x=-1,Slant: y=x+2

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asymptotes of f(x)=(x^2+3x)/(x+1)

asymptotes

f (x) = \frac{x ^{2} + 3 x}{x + 1}

Vertical : x = - 1, Slant : y = x + 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 3 x}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 3 x}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 3 x}{x + 1} : y = x + 2

Vertical : x = - 1, Slant : y = x + 2

f (x) = \frac{2 + x ^{2}}{1 - x ^{2}}

(x^{2} + 10) (4 - x^{2})

\frac{x ^{2} - 25}{2 x ^{2} - 17 x + 35}

f (x) = \frac{3 x + 15}{x ^{2} - 25}

f (x) = \frac{3 x ^{2} - 9 x}{5 x - 15}

What is the asymptotes of f(x)=(x^2+3x)/(x+1) ?
The asymptotes of f(x)=(x^2+3x)/(x+1) is Vertical: x=-1,Slant: y=x+2