What is the asymptotes of f(x)= 4/(x^2-9) ?

The asymptotes of f(x)= 4/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of f(x)= 4/(x^2-9)

asymptotes

f (x) = \frac{4}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{4}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{4}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{4}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

f (x) = \frac{5 x - 6}{3 ( 2 x - 7 )}

\frac{5 x}{x ^{2} - 16}

\frac{- 2 x - 8}{4 x - 12}

f (x) = \frac{2 x + 2}{3 x ^{2} - x - 4}

f (x) = \frac{2 x ^{2}}{x + 3}

What is the asymptotes of f(x)= 4/(x^2-9) ?
The asymptotes of f(x)= 4/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0