What is the asymptotes of f(x)=((4x^2-4))/(x^2+2x+1) ?

The asymptotes of f(x)=((4x^2-4))/(x^2+2x+1) is Vertical: x=-1,Horizontal: y=4

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asymptotes of f(x)=((4x^2-4))/(x^2+2x+1)

asymptotes

f (x) = \frac{( 4 x ^{2} - 4 )}{x ^{2} + 2 x + 1}

Vertical : x = - 1, Horizontal : y = 4

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} - 4}{x ^{2} + 2 x + 1} : x = - 1

Horizontal Asymptotes of

\frac{4 x ^{2} - 4}{x ^{2} + 2 x + 1} : y = 4

Slant Asymptotes of

\frac{4 x ^{2} - 4}{x ^{2} + 2 x + 1} :

None

Vertical : x = - 1, Horizontal : y = 4

f (x) = \frac{2 x ^{2} - 8}{x + 4}

f (x) = \frac{5 x ^{2} - 25 x}{3 x - 15}

\frac{- 4 x + 8}{x ^{2} - 7 x + 10}

f (x) = \frac{- 3 x ^{2} + 9 x - 6}{2 x ^{2} - 8}

f (x) = \frac{3 x ^{2} - 48}{2 x + 8}

What is the asymptotes of f(x)=((4x^2-4))/(x^2+2x+1) ?
The asymptotes of f(x)=((4x^2-4))/(x^2+2x+1) is Vertical: x=-1,Horizontal: y=4