What is the asymptotes of y=(2x^2+2x+3)/(4x^2-4x) ?

The asymptotes of y=(2x^2+2x+3)/(4x^2-4x) is Vertical: x=0,x=1,Horizontal: y= 1/2

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asymptotes of y=(2x^2+2x+3)/(4x^2-4x)

asymptotes

y = \frac{2 x ^{2} + 2 x + 3}{4 x ^{2} - 4 x}

Vertical : x = 0, x = 1, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 2 x + 3}{4 x ^{2} - 4 x} : x = 0, x = 1

Horizontal Asymptotes of

\frac{2 x ^{2} + 2 x + 3}{4 x ^{2} - 4 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{2 x ^{2} + 2 x + 3}{4 x ^{2} - 4 x} :

None

Vertical : x = 0, x = 1, Horizontal : y = \frac{1}{2}

f (x) = - lo g_{3} (x)

f (x) = arctan (e^{- 4 x})

f (x) = tan (x - \frac{π}{8})

f (x) = \frac{15 x - 18}{x - 5}

\frac{2 x - 10}{- 3 x - 8}

What is the asymptotes of y=(2x^2+2x+3)/(4x^2-4x) ?
The asymptotes of y=(2x^2+2x+3)/(4x^2-4x) is Vertical: x=0,x=1,Horizontal: y= 1/2