What is the asymptotes of f(x)=2x+8/(x^2) ?

The asymptotes of f(x)=2x+8/(x^2) is Vertical: x=0,Slant: y=2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=2x+8/(x^2)

asymptotes

f (x) = 2 x + \frac{8}{x ^{2}}

Vertical : x = 0, Slant : y = 2 x

Solution steps

Vertical asymptotes of

2 x + \frac{8}{x ^{2}} : x = 0

Horizontal Asymptotes of

2 x + \frac{8}{x ^{2}} :

None

Slant Asymptotes of

2 x + \frac{8}{x ^{2}} : y = 2 x

Vertical : x = 0, Slant : y = 2 x

f (x) = x^{3} - 3 x^{2} + 4

f (x) = \frac{1}{1 + x ^{2}}

f (x) = \frac{2 x ^{2} + 18 x - 20}{3 x ^{2} - 27 x + 60}

f (x) = \frac{3 x + 18}{x - 5}

f (x) = \frac{x + 6}{2 x - 3}

What is the asymptotes of f(x)=2x+8/(x^2) ?
The asymptotes of f(x)=2x+8/(x^2) is Vertical: x=0,Slant: y=2x