What is the asymptotes of ((0.3x^2-9))/(x^2-4x+2) ?

The asymptotes of ((0.3x^2-9))/(x^2-4x+2) is Vertical: x=2-sqrt(2),x=2+sqrt(2),Horizontal: y=0.3

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asymptotes of ((0.3x^2-9))/(x^2-4x+2)

asymptotes

\frac{( 0.3 x ^{2} - 9 )}{x ^{2} - 4 x + 2}

Vertical : x = 2 - 2, x = 2 + 2, Horizontal : y = 0.3

Solution steps

Vertical asymptotes of

\frac{0.3 x ^{2} - 9}{x ^{2} - 4 x + 2} : x = 2 - 2, x = 2 + 2

Horizontal Asymptotes of

\frac{0.3 x ^{2} - 9}{x ^{2} - 4 x + 2} : y = 0.3

Slant Asymptotes of

\frac{0.3 x ^{2} - 9}{x ^{2} - 4 x + 2} :

None

Vertical : x = 2 - 2, x = 2 + 2, Horizontal : y = 0.3

\frac{x ^{2} - 5 x + 6}{x - 1}

- \frac{2}{x + 4}

f (x) = \frac{x ^{2} - 9 x}{x ^{2} - 9}

f (x) = \frac{4 x + 16}{x ^{2} + x - 12}

f (x) = \frac{x ^{2} - 9}{x ^{2} - 5 x + 6}

What is the asymptotes of ((0.3x^2-9))/(x^2-4x+2) ?
The asymptotes of ((0.3x^2-9))/(x^2-4x+2) is Vertical: x=2-sqrt(2),x=2+sqrt(2),Horizontal: y=0.3