渐近线 f(x)=sqrt(x^2+10x+15)-x

解答

渐近线

f (x) = x^{2} + 10 x + 15 - x

水平 : y = 5, Slant : y = - 2 x - 5

求解步骤

x^{2} + 10 x + 15 - x

的垂直渐近线:

无

x^{2} + 10 x + 15 - x

的水平渐近线:

y = 5

Slant Asymptotes of

x^{2} + 10 x + 15 - x : y = - 2 x - 5

水平 : y = 5, Slant : y = - 2 x - 5

f (x) = \frac{7 x}{x ^{2} - 16}

f (x) = - 6^{3 x}

f (x) = \frac{x}{( x ^{2} - 9 )}

f (x) = 3^{x + 2} - 2

f (x) = 5^{x} - 8