What is the asymptotes of f(x)=(2x^2+4x-9)/(2x+1) ?

The asymptotes of f(x)=(2x^2+4x-9)/(2x+1) is Vertical: x=-1/2 ,Slant: y=x+3/2

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asymptotes of f(x)=(2x^2+4x-9)/(2x+1)

asymptotes

f (x) = \frac{2 x ^{2} + 4 x - 9}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = x + \frac{3}{2}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 4 x - 9}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{2 x ^{2} + 4 x - 9}{2 x + 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} + 4 x - 9}{2 x + 1} : y = x + \frac{3}{2}

Vertical : x = - \frac{1}{2}, Slant : y = x + \frac{3}{2}

x + ln (x^{2} - 3)

\frac{3 x}{x ^{2} - 25}

f (x) = e^{- 0.5 x^{2}}

\frac{x - 6}{x + 2}

y = \frac{2 x + 1}{x - 2}

What is the asymptotes of f(x)=(2x^2+4x-9)/(2x+1) ?
The asymptotes of f(x)=(2x^2+4x-9)/(2x+1) is Vertical: x=-1/2 ,Slant: y=x+3/2