What is the asymptotes of f(x)=(2x^2+3x)/(x+1) ?

The asymptotes of f(x)=(2x^2+3x)/(x+1) is Vertical: x=-1,Slant: y=2x+1

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asymptotes of f(x)=(2x^2+3x)/(x+1)

asymptotes

f (x) = \frac{2 x ^{2} + 3 x}{x + 1}

Vertical : x = - 1, Slant : y = 2 x + 1

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 3 x}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{2 x ^{2} + 3 x}{x + 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} + 3 x}{x + 1} : y = 2 x + 1

Vertical : x = - 1, Slant : y = 2 x + 1

f (x) = \frac{1}{x ^{2}} + \frac{1}{x}

f (x) = \frac{2 x ^{2} - 5 x - 3}{( x - 2 ) ^{2}}

f (x) = - 3

y = \frac{x ^{3}}{2 ( x + 1 ) ^{2}}

f (x) = \frac{4 x + 8}{x ^{2} + 2 x}

What is the asymptotes of f(x)=(2x^2+3x)/(x+1) ?
The asymptotes of f(x)=(2x^2+3x)/(x+1) is Vertical: x=-1,Slant: y=2x+1