What is the asymptotes of f(x)=(x^2-2x-8)/(2x^2-8x) ?

The asymptotes of f(x)=(x^2-2x-8)/(2x^2-8x) is Vertical: x=0,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2-2x-8)/(2x^2-8x)

asymptotes

f (x) = \frac{x ^{2} - 2 x - 8}{2 x ^{2} - 8 x}

Vertical : x = 0, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x - 8}{2 x ^{2} - 8 x} : x = 0

Horizontal Asymptotes of

\frac{x ^{2} - 2 x - 8}{2 x ^{2} - 8 x} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} - 2 x - 8}{2 x ^{2} - 8 x} :

None

Vertical : x = 0, Horizontal : y = \frac{1}{2}

f (x) = \frac{5 x + 2}{4 x + 8}

f (x) = lo g_{10} (x + 2)

f (x) = \frac{5}{x - 4}

f (x) = x^{4} - 12 x^{3} + 48 x^{2} - 64 x

\frac{5 x - 10}{x ^{2} - 4}

What is the asymptotes of f(x)=(x^2-2x-8)/(2x^2-8x) ?
The asymptotes of f(x)=(x^2-2x-8)/(2x^2-8x) is Vertical: x=0,Horizontal: y= 1/2