What is the asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) ?

The asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) is Vertical: x=4,Horizontal: y=1

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asymptotes of f(x)=(x^2+2x)/(x^2-2x-8)

asymptotes

f (x) = \frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8}

Vertical : x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 2 x}{x ^{2} - 2 x - 8} :

None

Vertical : x = 4, Horizontal : y = 1

f (x) = 4^{x - 3} + 1

f (x) = \frac{1}{x + 1} + 2

\frac{- 3 x ^{2} + 21 x - 36}{5 x - 20}

\frac{5 x - 1}{4 x + 2}

\frac{8 x ^{2} - 3}{2 x ^{2} + x}

What is the asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) ?
The asymptotes of f(x)=(x^2+2x)/(x^2-2x-8) is Vertical: x=4,Horizontal: y=1