What is the asymptotes of (x^2+2x-8)/(x+1) ?

The asymptotes of (x^2+2x-8)/(x+1) is Vertical: x=-1,Slant: y=x+1

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asymptotes of (x^2+2x-8)/(x+1)

asymptotes

\frac{x ^{2} + 2 x - 8}{x + 1}

Vertical : x = - 1, Slant : y = x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x - 8}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 2 x - 8}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 2 x - 8}{x + 1} : y = x + 1

Vertical : x = - 1, Slant : y = x + 1

f (x) = \frac{x}{x ^{2} + 64}

\frac{- 4 x ^{2} + 4 x}{5 x ^{2} - 25 x + 20}

f (x) = \frac{x ^{2} + 1}{x - 2}

f (x) = arctan (- e^{- 5 x})

f (x) = \frac{2 x + 6}{- 6 x + 3}

What is the asymptotes of (x^2+2x-8)/(x+1) ?
The asymptotes of (x^2+2x-8)/(x+1) is Vertical: x=-1,Slant: y=x+1