What is the asymptotes of (5x^2-10x+5)/(2x^2-x-1) ?

The asymptotes of (5x^2-10x+5)/(2x^2-x-1) is Vertical: x=-1/2 ,Horizontal: y= 5/2

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asymptotes of (5x^2-10x+5)/(2x^2-x-1)

asymptotes

\frac{5 x ^{2} - 10 x + 5}{2 x ^{2} - x - 1}

Vertical : x = - \frac{1}{2}, Horizontal : y = \frac{5}{2}

Solution steps

Vertical asymptotes of

\frac{5 x ^{2} - 10 x + 5}{2 x ^{2} - x - 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{5 x ^{2} - 10 x + 5}{2 x ^{2} - x - 1} : y = \frac{5}{2}

Slant Asymptotes of

\frac{5 x ^{2} - 10 x + 5}{2 x ^{2} - x - 1} :

None

Vertical : x = - \frac{1}{2}, Horizontal : y = \frac{5}{2}

\frac{1}{cos ( x )}

2 - 3 e^{- \frac{2}{x}}

f (x) = \frac{x - 5}{2 ( 3 x + 2 ) ( x - 5 )}

f (x) = \frac{7 x}{x ^{2} - 49}

f (x) = \frac{- x + 1}{x + 2}

What is the asymptotes of (5x^2-10x+5)/(2x^2-x-1) ?
The asymptotes of (5x^2-10x+5)/(2x^2-x-1) is Vertical: x=-1/2 ,Horizontal: y= 5/2