What is the asymptotes of f(x)=(8x^2)/(4x^3+2x^2-1) ?

The asymptotes of f(x)=(8x^2)/(4x^3+2x^2-1) is Vertical: x= 1/2 ,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(8x^2)/(4x^3+2x^2-1)

asymptotes

f (x) = \frac{8 x ^{2}}{4 x ^{3} + 2 x ^{2} - 1}

Vertical : x = \frac{1}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{8 x ^{2}}{4 x ^{3} + 2 x ^{2} - 1} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{8 x ^{2}}{4 x ^{3} + 2 x ^{2} - 1} : y = 0

Slant Asymptotes of

\frac{8 x ^{2}}{4 x ^{3} + 2 x ^{2} - 1} :

None

Vertical : x = \frac{1}{2}, Horizontal : y = 0

2^{x} - 1

f (x) = \frac{2 x ^{3}}{x ^{2} - 1}

f (x) = \frac{5 x}{x ^{2} - 25}

f (x) = \frac{x - 5}{x + 2}

f (x) = \frac{3 x ^{2} - 12 x + 12}{2 x - 2}

What is the asymptotes of f(x)=(8x^2)/(4x^3+2x^2-1) ?
The asymptotes of f(x)=(8x^2)/(4x^3+2x^2-1) is Vertical: x= 1/2 ,Horizontal: y=0