What is the asymptotes of f(x)=(2x-6)/(x^2-9) ?

The asymptotes of f(x)=(2x-6)/(x^2-9) is Vertical: x=-3,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(2x-6)/(x^2-9)

asymptotes

f (x) = \frac{2 x - 6}{x ^{2} - 9}

Vertical : x = - 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x - 6}{x ^{2} - 9} : x = - 3

Horizontal Asymptotes of

\frac{2 x - 6}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{2 x - 6}{x ^{2} - 9} :

None

Vertical : x = - 3, Horizontal : y = 0

\frac{x ^{2} + 5 x + 4}{x ^{2} - 13 x + 40}

f (x) = \frac{x ^{4} - 1}{x ^{2}}

\frac{1}{x - 2} - 3

\frac{5 x - 15}{x ^{2} - 8 x + 15}

f (x) = \frac{x ^{2}}{e ^{x + 1}}

What is the asymptotes of f(x)=(2x-6)/(x^2-9) ?
The asymptotes of f(x)=(2x-6)/(x^2-9) is Vertical: x=-3,Horizontal: y=0