What is the asymptotes of f(x)=(4x+7)/(6x^2-5) ?

The asymptotes of f(x)=(4x+7)/(6x^2-5) is Vertical: x=-sqrt(5/6),x=sqrt(5/6),Horizontal: y=0

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asymptotes of f(x)=(4x+7)/(6x^2-5)

asymptotes

f (x) = \frac{4 x + 7}{6 x ^{2} - 5}

Vertical : x = - \frac{5}{6}, x = \frac{5}{6}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{4 x + 7}{6 x ^{2} - 5} : x = - \frac{5}{6}, x = \frac{5}{6}

Horizontal Asymptotes of

\frac{4 x + 7}{6 x ^{2} - 5} : y = 0

Slant Asymptotes of

\frac{4 x + 7}{6 x ^{2} - 5} :

None

Vertical : x = - \frac{5}{6}, x = \frac{5}{6}, Horizontal : y = 0

f (x) = arctan (e^{- 2 x})

f (x) = 15 x^{\frac{2}{3}} - 10 x

f (x) = \frac{x ^{2} + 2 x - 3}{x ^{2} + x - 2}

4^{x - 2}

f (x) = \frac{x ^{2} - 2 x + 2}{3 x - \frac{1}{2}}

What is the asymptotes of f(x)=(4x+7)/(6x^2-5) ?
The asymptotes of f(x)=(4x+7)/(6x^2-5) is Vertical: x=-sqrt(5/6),x=sqrt(5/6),Horizontal: y=0