What is the asymptotes of f(x)=(x^2+2x-4)/(x^3+1) ?

The asymptotes of f(x)=(x^2+2x-4)/(x^3+1) is Vertical: x=-1,Horizontal: y=0

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asymptotes of f(x)=(x^2+2x-4)/(x^3+1)

asymptotes

f (x) = \frac{x ^{2} + 2 x - 4}{x ^{3} + 1}

Vertical : x = - 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x - 4}{x ^{3} + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 2 x - 4}{x ^{3} + 1} : y = 0

Slant Asymptotes of

\frac{x ^{2} + 2 x - 4}{x ^{3} + 1} :

None

Vertical : x = - 1, Horizontal : y = 0

f (x) = \frac{2 x ^{3}}{x ^{2} - x + 1}

f (x) = \frac{x + 2}{x ( x - 2 )}

\frac{3 e ^{x} + 6}{2 e ^{x} + 3} + 3

\frac{x ^{3} - 2}{x ^{4}}

f (x) = \frac{3 x ^{3} + x ^{2} + 1}{x ^{2} + 2 x}

What is the asymptotes of f(x)=(x^2+2x-4)/(x^3+1) ?
The asymptotes of f(x)=(x^2+2x-4)/(x^3+1) is Vertical: x=-1,Horizontal: y=0