What is the asymptotes of f(x)=(x^2-4)/(2x+1) ?

The asymptotes of f(x)=(x^2-4)/(2x+1) is Vertical: x=-1/2 ,Slant: y= 1/2 x-1/4

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asymptotes of f(x)=(x^2-4)/(2x+1)

asymptotes

f (x) = \frac{x ^{2} - 4}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = \frac{1}{2} x - \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{x ^{2} - 4}{2 x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} - 4}{2 x + 1} : y = \frac{1}{2} x - \frac{1}{4}

Vertical : x = - \frac{1}{2}, Slant : y = \frac{1}{2} x - \frac{1}{4}

\frac{sin ( x )}{x}

f (x) = \frac{4}{x + 5}

f (x) = \frac{x ^{2} - 4}{2 x ^{2} - 11 x + 14}

f (x) = lo g_{10} (x + 1)

f (x) = \frac{3 x - 15}{x + 2}

What is the asymptotes of f(x)=(x^2-4)/(2x+1) ?
The asymptotes of f(x)=(x^2-4)/(2x+1) is Vertical: x=-1/2 ,Slant: y= 1/2 x-1/4