What is the asymptotes of g(x)=(x^3-2x+1)/(3-x^4) ?

The asymptotes of g(x)=(x^3-2x+1)/(3-x^4) is Vertical: x=-\sqrt[4]{3},x=\sqrt[4]{3},Horizontal: y=0

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asymptotes of g(x)=(x^3-2x+1)/(3-x^4)

asymptotes

g (x) = \frac{x ^{3} - 2 x + 1}{3 - x ^{4}}

Solution steps

Vertical asymptotes of

Horizontal Asymptotes of

\frac{x ^{3} - 2 x + 1}{3 - x ^{4}} : y = 0

Slant Asymptotes of

\frac{x ^{3} - 2 x + 1}{3 - x ^{4}} :

None

f (x) = 3 \cdot 2^{x - 4}

f (x) = \frac{- 9 x ^{2} - 6 x}{x + 2}

f (x) = \frac{3 x ^{2}}{x ^{2} + 1}

f (x) = \frac{2 x ^{2}}{x ^{2} + 4}

f (x) = \frac{3 x ^{2}}{x ^{2} - 9}

What is the asymptotes of g(x)=(x^3-2x+1)/(3-x^4) ?
The asymptotes of g(x)=(x^3-2x+1)/(3-x^4) is Vertical: x=-\sqrt[4]{3},x=\sqrt[4]{3},Horizontal: y=0